**Solution:** The correct answer is 4.

Explanation: To determine how many of the given numbers are divisible by 132, we can break down 132 into its prime factors:

\[

132 = 2 \times 2 \times 3 \times 11

\]

So, a number must be divisible by 4, 3, and 11 to be divisible by 132.

– **Divisibility by 4:** The last two digits of the number should be divisible by 4.

– **Divisibility by 3:** The sum of the digits of the number should be divisible by 3.

– **Divisibility by 11:** The difference between the sum of the digits in odd positions and the sum of the digits in even positions should be divisible by 11.

Let’s check each number:

1. **660**:

– Last two digits: 60 (divisible by 4)

– Sum of digits: 6 + 6 + 0 = 12 (divisible by 3)

– Difference in sums (6+0) – (6) = 0 (divisible by 11)

– **Divisible by 132**

2. **754**:

– Last two digits: 54 (divisible by 4)

– Sum of digits: 7 + 5 + 4 = 16 (not divisible by 3)

– **Not divisible by 132**

3. **924**:

– Last two digits: 24 (divisible by 4)

– Sum of digits: 9 + 2 + 4 = 15 (divisible by 3)

– Difference in sums (9+4) – (2) = 11 (divisible by 11)

– **Divisible by 132**

4. **1452**:

– Last two digits: 52 (divisible by 4)

– Sum of digits: 1 + 4 + 5 + 2 = 12 (divisible by 3)

– Difference in sums (1+5) – (4+2) = 0 (divisible by 11)

– **Divisible by 132**

5. **1526**:

– Last two digits: 26 (not divisible by 4)

– **Not divisible by 132**

6. **1980**:

– Last two digits: 80 (divisible by 4)

– Sum of digits: 1 + 9 + 8 + 0 = 18 (divisible by 3)

– Difference in sums (1+8) – (9+0) = 0 (divisible by 11)

– **Divisible by 132**

7. **2045**:

– Last two digits: 45 (not divisible by 4)

– **Not divisible by 132**

8. **2170**:

– Last two digits: 70 (not divisible by 4)

– **Not divisible by 132**

Therefore, the numbers 660, 924, 1452, and 1980 are divisible by 132, so the correct answer is 4.